Horizontal CURVE Culculation

Horizontal CURVE Culculation

CURVE DIFINIATION AND FORMULAS

          first of all you have some data for soulation

Like you have deflection angle ,change intersection point ( I.P)

Degree of curve

^if YOU HAVE THAT DATA YOU CAN SOLVE THE CURVE OK LETS START

If you have no Deflection angle  you can find on this formula

          Deflection angle = 0 = 180 - Intersection angle

WE HAVE

GIVEN DATA .

Deflection angle = 40⁰

chain-age intersection point =I.P=17634.25

Degree of curve = D = 5⁰

Required Data

Tangent point one= TP1=?

Tangent point two =TP2 =?

SOLOUTION

Ist TP1 = change I.P –Tangent length

SO

First we will find Tangent length

Formula we have

Tangent Length =T.L= R Tan 0/2

we have no “R”

Formula for finding “Radius”

  5730/D

D= Degree of curve we have 5⁰

   5730/5 =1146

“1146” put this value in tangent length formula

     Tangent length = 1146 tan 40/2 =417.72

Now we have Tangent length “417.72”

Put this value in this formula

 Ist TP1 = chainage I.P –Tangent length

                  = 17634.25 – 417.72 =17217.13

Tangent point one(TP1) = 17217.13 ft

Now for “TP2”

Formula we have

                  Tangent point = TP1 + Curve Length

First we find curve length

Formula we have

    Curve Length = 3.14 R 0/180

                               3.14*1146/180 =800.16

Put this value in this ”800.16” formula

                     Tangent point = TP1 + Curve Length

                                               =17217.13+800.16 = 18017.29 ft

Now we can find curve ordinate

On these formulas

For middle ordinate

   For 1^st ordinate we have formula

R = Radius of curve

X = R .D

L = Length of curve